Physics, asked by prashmpatil19140, 6 months ago

The carbon monoxide (CO) molecule has bond length of 1.13 A° and
the masses of C and O atoms respectively are 1.99 x 10-26 kg and
2.66 x 10-26 kg. Find the reduced mass and moment of inertia of the
CO molecule.
(Ans. 1.14 x 10-26 kg, 1.461 x 10-46 kg-m3)​

Answers

Answered by aslamm1
2

Answer:

F=  

R  

2

 

GM  

e

​  

M  

m

​  

 

​  

 

F=  

(3.84×10  

8

)  

2

 

6.7×10  

−11

×6×10  

24

×7.4×10  

22

 

​  

 

=  

(3.84)  

2

×10  

16

 

297.48×10  

−11+24+22

 

​  

 

=20.17×10  

19

 

=2.017×10  

20

 N

Explanation:

Answered by syed2020ashaels
1

Answer:

The answer to this question is:1.14 * 10^-26 kg,1.461 * 10^-46 kg-m^2.

Explanation:

The reduced mass of a molecular system is a measure of the effective mass of the system when considering the motion of the constituent particles in the molecule. It is calculated as the harmonic mean of the individual masses of the constituent particles.

The moment of inertia of a molecular system is a measure of its resistance to rotational motion. It is calculated as the sum of the individual moments of inertia of the constituent particles.

In the case of the CO molecule, the reduced mass can be calculated as:

-\mu  = (m1 * m2) / (m1 + m2) = (1.99 * 10-26 kg * 2.66 * 10-26 kg) / (1.99 * 10-26 kg + 2.66 * 10^-26 kg) = 1.14 * 10^-26 kg

The moment of inertia of the CO molecule can be calculated as:

I = \mu * r^2 = 1.14 * 10^-26 kg * (1.13 * 10^-10 m)^2 = 1.461 *10^-46 kg-m^2

So the reduced mass of the CO molecule is 1.14 x 10-26 kg, and its moment of inertia is 1.461 x 10-46 kg-m^2.

#SPJ3

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