The carbonate of a metal is isomorphous with magnesium carbonate. It contains 6.09% of carbon. Atomic mass of metal is
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Since the unknown metal carbonate is isomorphic with MgCO3
Let the formula of the unknown be XCO3 and atomic weight of X be x a.m.u
Molecular weight of XCO3 = (x + 12 + 48)g = (60 + x)g
% composition of carbon = {12/(60 + x)} * 100%
ATQ,
{12/(60 + x)} * 100% = 6.091%
=>{12/(60 + x)} * 100 = 6.091
=>{12/(60 + x)} = 0.06091
=>12 = 60*0.06091 + 0.06091x
=>12 = 3.6546 + 0.06091x
=>0.06091x = 8.3454
=>x = 137.01
Therefore the atomic weight of the metal is 137.01 a.m.u and it can be recognized as barium
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