The cartesian form of 8cis(π) is
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0
Answer:
In this case, r=1 and θ=π4 . So, just plug in these values to get your coordinates. Therefore, the Cartesian form of (1,π4) is (√22,√22)
Answered by
1
Answer:
In this case, r=1 and θ=π4 . So, just plug in these values to get your coordinates. Therefore, the Cartesian form of (1,π4) is (√22,√22) .
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