Question

The Cartesian product A×A has 9 elements among which are found (-1,0) and (0,1) .Find the set A and the remaining elements of A×A. ​​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

A x A has 9 elements = n(AxA)=9

such that n(3x3)=9

so A = {a,b,c}

here, (-1,0) and (0,1) are in AxA

(-1,0) ---> a = -1 , b = 0

(0,1) ----> b = 0 , c = 1

A = {-1,0,1}

A x A = {-1,0,1} x {-1,0,1}

         = {(-1,-1),(-1,0),(-1,1),(0,-1),(0,0),(0,1),(1,-1),(1,0),(1,1)}

The remaining elements are (-1,-1), (-1,1), (0,-1), (0,0), (1,-1), (1,0), (1,1)