The cartisian coordinate of point on the parabollay=-16x whose parameter is 1/2
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Step-by-step explanation:
Given parabola is y
2
=−16x,
A point on the parabola of the form y 2
=4ax is (at
2 ,2at),----(i)
Here a=−4 and given the value of parameter is t=
2 1
substituting value of a and t in equation i,we get,
∴ The point is (−1,−4).
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