Question

The cast of 2 aronges and I apples i
0 146 and the
cast of 3 orange and I apples
is B 74.
1er us find the
cast of an orange
and and apple​

Answer 1

$\huge \bold { \underline{Correct \: Question?}}$

The cost of 2 oranges and 3 apples is 46 and the cost of 3 oranges and 5 apples is 74.

Find the cost of an orange and an apple.

$\huge \bold { \underline{Solution}}$

Given:-

• The cost of 2 oranges and 3 apples is 46.
• The cost of 3 oranges and 5 apples is 74.

To prove:-

• Cost of an orange and an apple.

Solution:-

➣Let the cost of oranges be x.

➣Let the cost of apples be y.

According To Question:-

$➣2x + 3y = 46$

$➣3x + 5y = 74$

Now multiply equation (i) by 3 and equation (ii) by 2.

$➣6x + 9y = 138$

$➣6x + 10y = 148$

_________________________________

$➣ - 1y = - 10$

$y = 10$

In substituting in (I) for X we will get X=

$➣2x + 3y = 46$

$➣2x + 30 = 46$

$➣2x = 46 - 30$

$2x = 16$

$x = 18$

So the cost of:-

• Orange:- 18
• Apple:- 10.