Chemistry, asked by chauhandivyansh786, 8 months ago

The catalytic decomposition of phosphine 4 PH3(g) ---> P4 + 6H2(g) has rate law as rate = k[ PH3]. the rate constant is 6.0 x 10^-4 s^-1 at 300 k and E^a is 3.05 x 10^5 J/mol. What is the value of rate constant at 310 k?

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Answered by Anonymous
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