The catapult hurls a stone of mass 32g with the velocity of 60ms-1 at an angle of 45 what is the maximum height reached by the stone
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Answer:
90m
Explanation:
Hmax=U²sin²θ/2g
Hmax=(60×60)(1/√2)²/2(10) [Assuming g as 10m/s²]
Hmax=60×30/20
Hmax=90m
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