The Ce (Z = 58) belongs to IIIrd group of periodic table. If it
furnish one α particle to form an element 'X', then X belongs
to
(a) IIIʳᵈ group (b) IIⁿᵈ group
(c) Iˢᵗ group (d) zero group
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If Ce (Z = 58) furnish one α particle to form an element 'X', then X belongs
to IIⁿᵈ group
- when an element loses an α particle, its atomic no (Z) is decreased by 2 and its mass no decreases by 4
- so when Cerium loses an alpha particle,then the atomic no of resultant element X = 58 - 2
= 56
- this element X with Z = 56 is Barium and it belongs to the IInd group of the periodic table
-so the correct answer is option (b)
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