Question

The ceiling of a tunnel is 5m high. What is the maximum horizontal distance that a ball thrown with a speed of 20m/s, can go without hitting the tunnel? take g = 10m/s square.

Answer 1

The maximum horizontal distance travel by the ball is 17.32 m.

in projectile motion, the maximum height reached by a body projected at an angle ∅, Is given by the  relation:

h=$\frac{u^2sin^2∅}{2g}$

Since the heigh of the tunnel is 5m

5=$\frac{20^2*sin^2∅}{2*10}$

∅=30 degree

Now the maximum horizontal distance that a ball can travel is calculated as

R=$\frac{20^2*sin2(30)}{2*10}$

R=17.32 m

Therefore, The maximum horizontal distance travel by the ball is 17.32 m.

Answer 2

Answer:

The answer to this question is 20√3m