Question

The ceiling of an ling ball is
25 m high . What is the maximum horizontal distance that a ball thrown with a speed of 40 ms^-1 can go without hitting the ceiling if the ball​

Answer 1

Answer:

first of all we have to find angle so,

H be the height of ceiling i.e., 25m

H=(u×u×sin^2(theta))/2g

where u=40m/s g=10m/s^2

so

25=(40×40×sin^2(theta))/2g

on solving we will get theta and then using it in formula

R =(u×u×sin(2theta))/g

on solving we will get R(range).