The ceiling of long hall is 25 m high .what is the maximum horizontal distance that a ball thrown with a speed of 40 m per second can go without heating the ceiling of the hole?
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Maximum height, h = 25 m
In projectile motion, the maximum height reached by a body projected at an angle θ, is given by the relation:
h = u2 Sin2θ / 2g
25 = (40)2 Sin2θ / 2 × 9.8
sin2 θ = 0.30625
sin θ = 0.5534
∴ θ = sin–1(0.5534) = 33.60°
Horizontal range, R = u2 Sin 2θ / g
= (40)2 × Sin (2 × 33.600) / 9.8
= 1600 × Sin (67.2) / 9.8
= 1600 × 0.922 / 9.8 = 150.53 m
Maximum height, h = 25 m
In projectile motion, the maximum height reached by a body projected at an angle θ, is given by the relation:
h = u2 Sin2θ / 2g
25 = (40)2 Sin2θ / 2 × 9.8
sin2 θ = 0.30625
sin θ = 0.5534
∴ θ = sin–1(0.5534) = 33.60°
Horizontal range, R = u2 Sin 2θ / g
= (40)2 × Sin (2 × 33.600) / 9.8
= 1600 × Sin (67.2) / 9.8
= 1600 × 0.922 / 9.8 = 150.53 m
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