The cell in which the following reaction occurs:
2Fe 3+ (aq) + 21 (aq) → 2Fe2+ (aq) +1, (s) has Ecel = 0.236 V at 298 K.
Calculate the standard Gibbs energy and the equilibrium constant of the
cell reaction.
Answers
Answered by
3
Answer:
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Answered by
8
Answer:
9.68×10*7
Explanation:
∆G = nFE°
= -2 × 96500 × 0.236 = -45.548 kJ
logK = nFE°/2.303RT = 2× 0.236/0.0591
= 7.986
K = (10)*7.986 = 96827785.6
= 9.68×10*7
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