The cell reaction of acell is Mg(s) + 2H+
(aq) Mg2+ (aq) +H2(g) .If the standard reduction potential of Zn is -2.372
V, then the emf of the cell is
(A) +2.372 V (B)-2.372 V (C) 0.00V (D)-1.372 V
Answers
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Answer:
a) +2.372V
Explanation:
E=Ecathode-Eanode
=0-(-2.372)
=2.372
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