Chemistry, asked by gmaheshkumar2002, 1 month ago

The cell reaction of acell is Mg(s) + 2H+

(aq) Mg2+ (aq) +H2(g) .If the standard reduction potential of Zn is -2.372

V, then the emf of the cell is
(A) +2.372 V (B)-2.372 V (C) 0.00V (D)-1.372 V​

Answers

Answered by umadevisasikumar6131
0

Answer:

a) +2.372V

Explanation:

E=Ecathode-Eanode

=0-(-2.372)

=2.372

Similar questions