Question

the center of a circle is (a+2,a-2). find the value of a if the circle passes through (2,-2) and (8,-2)
please answer it

Answer 1

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Answer 2

Hello user..here is your answer..❤❤

Given that circle passes through point (2,-2) and (8,-2)

It states that the circumference of the circle passes through these points.

We know that the distance between the radius and any point on the circumference of circle is equal

so, we can find the distance of the point through which it passes and the radius using distance formula.

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Distance formula :√ ( x2-x1)^2 + ( y2-y1)^2 ) = radius

therefore, √(2- a-2) ^2 +(-2-a+2)^2) = radius

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√ (-a)^2 +(-a )^2 = radius

____________

√2 a square = radius

Similarly,

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√(8-a-2)^2+(-2+2-a)^2 = radius

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√36+a^2 + a^2. = radius

therefore,

__________. ____________

√2a square = √36+a^2 + a^2.

Squaring both sides

so ,2 a^2 = 36+2a^2