The center of a circle is on the line y =2x and the line x=1 is tangent to the circle at (1, 6).
Find the center and radius of the circle.
Answers
Answered by
1
Answer:
x=1
y=2x=2*1=2
(x,y)=(1,2)
C=2pir
=2*3.14*(1-2)'2
=6.28
Answered by
10
Center at (3,6) and radius is 2 units.
Step-by-step explanation:
Given that x = 1 line is tangent to the circle at point (1,6).
So, y = 6 will be the equation of the radius line of the circle through the point (1,6).
{Since the tangent line and the radius line are perpendicular to each other}
Therefore, the intersection point of the lines y = 2x and y = 6 will be the center of the circle.
{Since the center of the circle lies on the line y = 2x}
Now, the solution point i.e. the intersection point of lines y = 2x and y = 6 is point (3,6).
Hence, the center of the circle is at point (3,6) and its radius is the distance between points (1,6) and (3,6) i.e. 2 units. (Answer)
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