The center of circle is (3,4)and it passes through (2,5) what is it's radious
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centre of circle is (3,4)
and it passes through (2,5)
as radius is just distance between any point on circle and centre
So, radius = √[(5-4)^2 +(2-3)^2]
=√(1+1)
=√2
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centre of circle is (3,4)
centre of circle is (3,4)and it passes through (2,5)
centre of circle is (3,4)and it passes through (2,5)as radius is just distance between any point on circle and centre
centre of circle is (3,4)and it passes through (2,5)as radius is just distance between any point on circle and centreSo, radius = √[(5-4)^2 +(2-3)^2]
centre of circle is (3,4)and it passes through (2,5)as radius is just distance between any point on circle and centreSo, radius = √[(5-4)^2 +(2-3)^2]=√(1+1)
centre of circle is (3,4)and it passes through (2,5)as radius is just distance between any point on circle and centreSo, radius = √[(5-4)^2 +(2-3)^2]=√(1+1)=√2
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