Question

The center of mass of 3 particles of masses 1kg,2kg,3kg is at (2,2,2) the position of fourth mass of 4kg to be placed in the system so that the new center of mass is at (0,0,0) is

Answer 1

Answer:

(-3,-3,-3)

Explanation:

m1x1+m2x2+m3x3/m1+m2+m3=2

and m1x1+m2x2+m3x3+m4x4/m1+m2+m3+m4=0

hence substituting the numerator from equation 1 we get

x4=-2(m1+m2+m3)/m4=-3

U get similar equation for the y and z components hence the answer is(-3,-3,-3)