Question

The center of the circle O in the given shape is pa and pb. The letters of the circle are tangents.what is the degree of angle AOB​

Answer 1

Answer:

Tangents and radii are perpendicular at the point of contact.

In quadrilateral OAPB, we have:

∠APB=80

o

, ∠OAP=∠OBP=90

o

By angle sum property of quadrilateral:

⇒∠AOB=100

o

Now, we know that angle subtended at the center is twice the angle subtended at any point on the arc, so we have:

∠AQB=

2

1

∠AOB=50

o

.

So option D is the right answer.