Math, asked by arka2740, 1 month ago

The center of the circle x^2+y^2-8x+10y-2=0 is

Answers

Answered by dkchakrabarty01

0

Answer:

x^2-8x+16+y^2+10y +25 -16-25-2=0

(x-4)^2+(y+5)^2-41-2=0

coordinates of centre are 4and-5

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