Question

The center of the the mass of the apple is 25cm from the pivot and the center of the mass of weights is 45cm from the pivot calculate the weight of the apple

Answer 1

Explanation:

hope it will help you

Answer 2

Your question seems incomplete. A complete question is -> a figure shows an apple and a 0.40 N weight placed on the rule so that the rule remains balanced at the 50 cm mark. The centre of mass of the apple is 25 cm from the pivot and the centre of mass of the weight is 45 cm from the pivot.

We have to find the weight of the apple.

Let the weight of the apple is w.

To balance the rule,

⇒ torque due to apple + torque due to an object of weight 0.4 N = 0

we know, Torque = weight of object × separation between point of observation to the axis of rotation.

so, τ₁ + τ₂ = 0

⇒ w × 25cm (anticlockwise) + 0.4 N × 45cm (clockwise) = 0

⇒w × 25 cm (anticlockwise) - 0.4 × 45 cm (anticlockwise) = 0

⇒w × 25 = 0.4 × 45

⇒w = $\frac{0.4\times45}{25}=0.72N$

Therefore the weight of the apple is 0.72 N