Question

The central fringe of a interference pattern produced by light of wavelength 6000 Angstrom is found to shift to the position of 4th bright fringe after a glass plate of refractive index 1.5 is introduced . The thickness of the glass plate would be (in mu-m)


1)4.8


2)8.23


3)14.98


4)3.78...........

Answer 1

⭐⭐⭐hey mate!⭐⭐⭐

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⚡⚡ANSWER= 4.8 mu-m

Explanation:-

⚡⚡Shift at nth bright is

(Mu-1)t=n lembda

Putting the value of

Mu=1.5

n=5

Lembda= 6000A°

We get,

(1.5-1)t =5 ×6000 ×10^-10

t= 4.8 mu-m

Hope it will help you..

#phoenix

Answer 2

Answer:

4.8................