the Central Hall of a school is 18m long and 12.5 M wide. a carpet is to be laid on the floor leaving a strip 50 cm wide near the wall UN covered. find the area of the carpet and also the uncovered portion
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86
Solution:-
Portion uncovered = 50 cm = 0.5 m
Length of the carpet = 18 m - (0.5 m + 0.5 m) = 17 m
Breadth = 12.5 m - (0.5 m + 0.5 m) = 11.5 m
Area of the carpet = 17*11.5
= 195.5 sq m
Area of the hall = 18*12.5
= 225 sq m
Now area of the uncovered portion = area of the hall - area of the carpet
= 225 - 195.5
Area of the uncovered portion = 29.5 sq m
Portion uncovered = 50 cm = 0.5 m
Length of the carpet = 18 m - (0.5 m + 0.5 m) = 17 m
Breadth = 12.5 m - (0.5 m + 0.5 m) = 11.5 m
Area of the carpet = 17*11.5
= 195.5 sq m
Area of the hall = 18*12.5
= 225 sq m
Now area of the uncovered portion = area of the hall - area of the carpet
= 225 - 195.5
Area of the uncovered portion = 29.5 sq m
Answered by
0
Answer:
Hey mate....am here to answer you!!!
Step-by-step explanation:
side of small square = 45m
so,area of a small square
=side×side
=45×45
=2025 square meters
side if big square
=45×2×(2.5)
=45+5.2
=50m
THEREFORE;area of a big square
=50×50
2,500 square meters
hope it helped if yes full fill ❤❤❤and
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