Question

The centre of a circle is (2 α - 1, 7} and passes through the point { - 3, - 1 ] if the diameter of the circle is 20 units then find the values of Alpha.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Radius of Circle = 10 units
O(2a - 1,7) = (x,y)
P(-3,-1) = (x1,y1)
Distance between center of Circle and the other point P =
$= > 10 = \sqrt{{(x - x1)}^{2} + {(y - y1) }^{2} } \\ = > 10 = \sqrt{{(2 \alpha - 1 + 3)}^{2} + {(7 + 1)}^{2} } \\ = > 10 = \sqrt{{(2 \alpha + 2 ) }^{2} + (8)^{2} } \\ = > {10}^{2} = {(2 \alpha + 2)} ^{2} + 64 \\ = > 100 - 64 = {(2 \alpha + 2)}^{2} \\ = > \sqrt{36 } = 2 \alpha + 2 \\ = > ±6 - 2 = 2\alpha \\ = > \frac{4}{2} = \alpha = 2 \\ or \\ \alpha =\frac{-8}{2} = -4$