The centre of a circle is (2, -3) and the circumference is
10π
. Then the equation of circle
(a) x^2 + y2 + 4x + 6y + 12 = 0
(b) x^2 + y2 - 4x + 6y + 12 = 0
(C) x2 + y2 - 4x + 6y - 12 = 0
(d) x + y2 - 4x - 6y - 12 = 0
e
Answers
Answered by
2
Answer:
please make me brainliest
Answered by
1
Answer:
x2+y2+4x+6y+12=0
Step-by-step explanation:
x2+y2
+4x+6y
+12 =0
because it is maths
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