Math, asked by ck176709, 8 months ago

the centre of a circle is 2a, a-7.
find the value of a if the circle passes through the point (11, -9) and has
diameter10√2​

Answers

Answered by jaswanthsaichunduri1
3

Step-by-step explanation:

the perimeter of circle= πr

=22/7 x 10/2

=22/7 x 5

=15.71

i hope it may help u............

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Answered by rishijakkam
2

Step-by-step explanation:

We will learn how the general equation of second degree represents a circle.

General second degree equation in x and y is

ax2 + 2hxy + by2 + 2gx + 2fy + C = 0, where a, h, b, g, f and c are constants.

If a = b(≠ 0 ) and h = 0, then the above equation becomes

ax2 + ay2 + 2gx + 2fy + c = 0

⇒ x2 + y2 + 2 ∙ ga x + 2 ∙ fa y + ca = 0, (Since, a ≠ 0)

⇒ x2 + 2 ∙ x ∙ ga + g2a2 + y2 + 2.y .fa + f2a2 = g2a2 + f2a2 - ca

⇒ (x + ga)2 + (y + fa)2 = (1ag2+f2−ca−−−−−−−−−−√)2

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