Question

The centre of a circle is (2a ,a-7)Find the values of a if the circle passes through the point(11,-9)and has the diameter root2 units

Answer 1

I think the diameter is not only.√2
here the diameter is 10√2
then radius =5√2

√(2a-11)²+(a-7+9)²=5√2
(2a-11)²+(a+2)²=(5√2)²
4a²-44a+121+a²+4a+4=50
5a²-40a+75=0
a²-8a+15=0
(a-3)(a-5)=0
a=3,5

Answer 2

Answer:

Step-by-step

diameter is 10√2

then radius =5√2

√(2a-11)²+(a-7+9)²=5√2

(2a-11)²+(a+2)²=(5√2)²

4a²-44a+121+a²+4a+4=50

5a²-40a+75=0

a²-8a+15=0

(a-3)(a-5)=0

a=3,5

So there are two values for a I.e. 3 and 5