Question

The centre of a circle is (2a, a – 7). Find the values of a, if the circle passes through the point (11, –9) and has a diameter 10√ 2 units.​

Answer 1

Step-by-step explanation:

diameter of circle = 10√2 units

radius = (10√2)/2 = 5√2 units

let P(x1, y1) = P(11,-9) &

Q(x-2, y2) = Q(2a, a-7)

so, PQ = 5√2 units

Using distance formula find the value of a

PQ = √[(x2 - x1)² + (y2 - y1)²]

Answer 2

Step-by-step explanation:

If the centre of a circle is (2a,a-7) ,then Find the value of a , if the circle passes through the point (11,-9) and has diameter 10sqrt(2) units . Hence , the required values of a are 5 and 3.