the centre of a circle is (3,5) and end points of a diameter are (4.7) and (2, y), then find the value of y.
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Answered by
0
Answer:
(x1 - x)(x2 - x) + (y1 - y)(y2 - y) = 0
(4 - 3)(2 - 3) + (7 - 5)(y - 5) = 0
- 1 + 2y - 10 = 0
2y = 11
y = 11/2
Step-by-step explanation:
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Answered by
1
Answer:
Y=3
Step-by-step explanation:
Let O(3,5) is the centre of a circle whose diameter is AB , thus , mid point of AB is thecentre of the circle. given that A(4,7) , B(2,y).y- coordinate of O = {(y-coordinate of A) +(y-coordinate of B)}/2.or, 5 = {(7)+(y)}/2.or, 7+y = 10.
or, y = 10 - 7 = 3.
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