Question

The centre of a circle whose end points of a diameter are (-6, 3) and (6, 4) is​

Answer 1

Given:

The end points of a diameter of a circle are:

(x1 , y2) = (-6 , 3)

(x2 , y2) = (6 , 4)

To Find:

Center of a circle = ?

Solution:

As we know,

midpoint of the X coordinates

X=(x1+x2)/2

On putting the values, we get

= ( - 6 + 6) /2

= 0

midpoint of the Y coordinates

Y=(y1+y2)/2

On putting the values, we get

= ( 3 + 4 )/2

= 7/2

= 3.5

Thus, the center co-ordinates of a circle will be "(0 , 7/2)".

OR

So the coordinates of the centre of the circle are ( 0 , 3.5 )