Question

The centre of a circle x + 2 x minus 1 find x is a circle passing through 2 - 2 and 8

Answer 1

Answer:

let the center be O(x+2,x-1)

given the circle passes through A(2,-2)and B(8,-2).

therefore OA=OB (radii)

so. OA^2 = OB^2

x sq. +(x+1) sq. =  (x-6) sq. + (x+1) sq.

x sq. +x sq. +1+2x=x sq. +36 - 12x +x sq. +1+2x\

0=36-12x

12x=36

x=3

answer. the value of x is 3....

Thanks.....