Question

The centre of a circle {x^2} + {y^2} -5x - 12y - 1 = 0 is​

Answer 1

Step-by-step explanation:

x² + y² - 5x - 12y - 1 = 0

from Comparing circle equation -

x² + y² + 2gx + 2fy + c = 0

2g = -5 , g = -5/2

2f = -12 , f = -6

Centre of this circle -

C ( -g , -f ) = ( 5/2 , 6 )

Answer 2

x² + y² - 5x - 12y - 1 = 0

from Comparing circle equation -

x² + y² + 2gx + 2fy + c = 0

2g = -5 , g = -5/2

2f = -12 , f = -6

Centre of this circle -

C ( -g , -f ) = ( 5/2 , 6 )

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