Math, asked by eknoorsingh53, 3 months ago

the centre of circle 3x^2 + 3y^2 -6x +9y -1 is​

Answers

Answered by rohanshetty864
1

Answer:

Step-by-step explanation:

The general equation of circle is x^2+y^2+ 2gx + 2fy+c= 0 where g & f are the co-ordinates of the center of circle

3x^2 + 3y^2 -6x +9y -1 ........ Given equation (1)

Compare equation (1) with x^2+y^2+ 2gx + 2fy+c= 0

so g = -3 & f= 4.5

So the co-ordinates of center are (g ,f)≡(-3,4.5)

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