Question

The centre of gravity at t section 100 mm into 150 mm into 50 mm from its bottom is quare solve

Answer 1

Answer:

Step-by-step explanation:

It is 87.5mm

Hope it helps you....

Answer 2

Answer:

Centre of the gravity is $87.5mm.$

Step-by-step explanation:

Given,

The centre of gravity at $T$ ssection $100mm$ into $150mm$ into $50mm$.

$y=\frac{a_1y_1+a_2y_2}{a_1+a_2}$

Vertical element:

$a_1=120*50=6000mm^2$

$x_1=\frac{100}{2} =50mm,y_1=\frac{h}{2}=\frac{120}{2} =60mm$

Harizontal element:

$a_2=100*50=1500mm^2$

$x_2=\frac{100}{2} =50mm,y_1=\frac{h}{2}+120=\frac{30}{2}+120 =135mm$

$x=\frac{(6000)(50)+(1500)(50)}{6000+1500}$

$x=\frac{(6000)(50)+(1500)(50)}{6000+1500}=50mm$

$y=\frac{(6000)(60)+(1500)(135)}{6000+1500}$

$y=\frac{(6000)(60)+(1500)(135)}{6000+1500}=75mm$

Centre of the gravity is $87.5mm.$