Question

The centre of gravity (centre of mass)
of a rod (of length L) whose linear
mass density varies as the square of
the distance from one end is at
(A)L/3
(B)3L/4
(C)3L/5
(D)2L/5​

Answer 1

Answer:

c ) 3 L/4

Le the linear density be ρ=kx2

Centre of Gravity=∫ρ∫xρ=∫0Lx2dx∫0Lx3dx=43L

Hope you understand. : )