Question

The centre of gravity of a solid cone of height h is at distance x from its

vertex. Find the value of x . ​

Answer 1

Answer:

The centre of gravity of a hollow cone is at a height h/3 from the base. Hence, from the vertex the height is h - h 3 = 2h 3 . Hence, the correct answer .

Answer 2

The value of x of a solid cone is 2h/3

Given:

The center of gravity of a solid cone of height h is at distance x

To Find:

realize the worth of x  of a solid cone of height h is at distance x from its vertex

Solution:

The center of gravity of a hollow cone is at a height  h/3 from the bottom. Hence, from the vertex the peak is ,

The Centre of gravity of a hollow cone of height h is at distance x from its vertex wherever the worth of x is,

The Centre of gravity of a hollow cone is at a height h/3 from the bottom.

The Centre of gravity of a hollow cone of height h is at distance x from its vertex wherever the worth of x is,

The Centre of gravity of a hollow cone is at a height h/3 from the bottom. Hence, from the vertex the peak is `"h" - "h"/3 = "2h"/3`.

= h - $\frac{h}{3}$

=  $\frac{2h}{3}$

The Centre of gravity of a hollow cone is at a height h/3 from the bottom. Hence, from the vertex the peak is `"h" - "h"/3 = "2h"/3`.

Hence, the worth of a solid cone of distance x is 2h/3

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