Question

the centre of mass of a body is moving with a uniform velocity of 10cm/s . three forces are applied on the body which are in equilibrium. the velocity of centre of mass would become :-​

Answer 1

Answer:

10cm/s

Explanation:

Answer 2

The given data:

• $Vcm=10cm/sec$
• Explanation:

  On applying  a force which are in equilibrium

Step -1      $\overrightarrow{F1} + \overrightarrow{F2} + \overrightarrow{F3} =0$

Step-2      $Fext = \frac{dp}{dt} =m \frac{dv}{dt}$

Step-3      $0= m\frac{dv}{dt}$

Step-4     $dv=0$

Step-5     $vf=v$

Step-6   $vf=10cm/sec$

Conclusion; The velocity of the center of mass would become $10cm/s$