Question

The centre of mass of a system of three particles of masses 1g, 2g and 3g is taken as the origin of a coordinate system. The position vector of a fourth particle of mass 4g such that the centre of mass of the four particle system lies at the point (1,2,3), is alpha(i^ +2j^+3k^), where alpha is constant. The value of alpha is


1) 10/5
2)5/2
3)1/2
4)2/5

Please answer with a proper explanation

Answer 1

Answer:hello

Explanation:

b)5/2

COM of y coordinate=(m1×y1 +m2×y2 +m3×y3 +m4×y4)/m1+m2+m3+m4

but the first three terms In the numerator is equal to zero,hence

COM=4×2a/10=2

therefore a=5/2