The centre of mass, of the system of threr
particles having masses and locations as show
in the figure, has coordinates (in m)
y(m)
3 kg (0,4)
(4,0)
6 kg
(0,0) 1Kg
x(m) option:(1) (1.2,2.4) (2) (2.4,2.4) (3) (1.2,1.2) (4) (2.4,1.2)
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Answer:
Answer is 4 i.e. (2.4,1.2)
Explanation:
Xcm= (m1×x1 + m2×x2 + m3×x3)÷(m1+m2+m3)
Ycm= (m1×y1 + m2×y2 + m3×y3)÷(m1+m2+m3)
The coordinates form a triangle
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