The centre of the circle (1+m?)(x² + y²) – 2cx – 2cmy = 0 is
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Find the centre and radius of the circle 1+m2 (x2+y2)−2cx−2mcy=0.
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The equation of the circle is given as √(1 + m2) (x2+y2) - 2cx - 2mcy = 0 . (x2+y2) - 2cx√(1 + m2) - 2mcy√(1 + m2) = 0 Comparing the given equation ... More
thanks for free point
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