Math, asked by sravya19, 8 months ago

The centre of the circle (1+m?)(x² + y²) – 2cx – 2cmy = 0 is​

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Answered by kirangusain84
3

Answer:

Find the centre and radius of the circle 1+m2 (x2+y2)−2cx−2mcy=0.

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The equation of the circle is given as √(1 + m2) (x2+y2) - 2cx - 2mcy = 0 . (x2+y2) - 2cx√(1 + m2) - 2mcy√(1 + m2) = 0 Comparing the given equation ... More

thanks for free point

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