the centre of the circle(2p-1,p).find the p if circle passes through the point (10,-2)and diameter is 10√2
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The given diameter is 10√2
Therefore, the radius of the circle is 5√2
Hence, the distance between (2p-1,p) and (10,-2) is the given radius.
We can solve the problem by using distance formula
5√2 = √((10-2p+1)^2+(-2-p)^2)
5√2= √((11-2p)^2+(-2-p)^2)
On squaring both sides and simplifying we get
45= 5p^2
p= +-3
Therefore, the radius of the circle is 5√2
Hence, the distance between (2p-1,p) and (10,-2) is the given radius.
We can solve the problem by using distance formula
5√2 = √((10-2p+1)^2+(-2-p)^2)
5√2= √((11-2p)^2+(-2-p)^2)
On squaring both sides and simplifying we get
45= 5p^2
p= +-3
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