Question

the centre of the circle(2p-1,p).find the p if circle passes through the point (10,-2)and diameter is 10√

Answer 1

Answer:

Step-by-step explanation:

here diameter

2r=10  

2

​  

 

r=5  

2

​  

 

OA=r=5  

2

​  

 

=  

(2a−1−10)+(a+2)  

2

 

​  

=5  

2

​  

 

(2a−11)  

2

+(a+2)  

2

=50

4a  

2

−44a+121+a  

2

+4a+4=50

5a  

2

−40a+75=0

a  

2

−8a+15=0

a−5a−3a+15=0

(a−5a)(a−3)=0

a=5or3

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