Math, asked by neelamlavanya99, 9 months ago

The centre of the circle circumscribing the
square whose three sides are
3x + y = 22, x - 3y = 14 and 3x + y = 62 is:
16:27
3) (27,3)
2) (16,6)
4) (1,)​

Answers

Answered by ravisher792gmailcom
7

Answer:

3x+y=22 x-3y= 14 3x+y=62

take x and y on one side and others on other side and change signs

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