Question

the centre of the circle for which 5x+12y-10=0 and 5x-12y -40=0 are tangents can be

Answer 1

Center of circle can be at ( x , - 5/4)

Step-by-step explanation:

Let say center of circle = (h , k)

Radius = r

5x+12y-10=0 and 5x-12y -40=0 are tangents

=> r  =  (5h + 12k - 10)/(√5² + 12²)  =  (5h - 12k - 40)/(√5² + 12²)

=> r = (5h + 12k - 10)/13 =  (5h - 12k - 40)/13

=> 5h + 12k - 10 = 5h - 12k - 40

=> 24k = -30

=> 4k = -5

=> k = -5/4

Center of circle can be at ( x , - 5/4)

Learn more:

Equation of the circle which is such that the lengths of the tangents ...

https://brainly.in/question/13068835

The angle between a pair of tangents drawn from a point P to the ...

https://brainly.in/question/9606826