Question

the centre of the circle having end points of it's one diameter as (-4,2)and (4,-3)​

Answer 1

Answer:

Let AB be a diameter of the circle having its centre at C(1, -3) such that the coordinates of one end A are (4, -1).

Let the coordinates of B be (x,y).

Since C is the mid-point of AB. Therefore,the coordinates of C are(

2

x+4

,

2

y−1

).

But, the coordinates of C are given to be (1,-3).

∴

2

x+4

=1and

2

y−1

=−3

⇒x+4=2andy−1=−6

⇒x=−2andy=−5

Hence,the coordinates of B are (-2, -5).

Step-by-step explanation:

hope it will help you

Answer 2

Answer:

hyy

Let AB be one of the diameters with end points A(-4,2) and B(4,-3)

The center of the circle is the mid point of AB

Midpointformula=(x1+x22,y1+y22)

midpoint=(−4+42,2−32)=(0,−1/2)

Center of the circle=(0,-1/2)

HOPE THIS HELPS YOU