Question

the centre of the circle is (2a,a-7) find the values of a if the circle passes through the point(11,-9) and has diameter 10root2 units

Answer 1

Answer:

If the diameter of circle is 10√2

then radius of circle =5√2

From eqn of circle,

(2a-11)² + (a-7+9)² = 50

4a² +121-44a + a² + 4a + 4 = 50

5a² - 40a + 75 = 0

5a² - 25a - 15a +75 = 0

5a (a-5) + 15 (a-5) = 0

(5a+ 15) (a-5) =0

a-5=0 or 5a + 15 = 0

a = 5 a = - 3

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