Question

The centre of the circle touching the y-axis at (0,3) and making an intercept of 2 units on the positive x-axis is​

Answer 1

Answer:

As given, the circle touches the Y-axis at (0,3). So, the point (0,3) must lie on the circle i.e. it must satisfy the equation of circle (equation (3)). It is also given that, circle makes an intercept of 2 on the positive X-axis. Thus, we get the centre of the circle as $\left( {\sqrt {10} ,3} \right)$ .

Step-by-step explanation: