The centre of the circle x = –1 + 2cosθ, y = 3 + 2sinθ, is
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from the question , we can write that
(x+1)^2 +(y-3)^2 =4
so, the centre of the circle is (-1,3)
(x+1)^2 +(y-3)^2 =4
so, the centre of the circle is (-1,3)
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