Question

. The centre of the circle x2 + y2 + 6x – 4y - 12 = 0 is ​

Answer 1

Answer:

x^2+y^2+6x-4y-12=0

=> x^2+6x+9+y^2-4y+4-12=9+4

=> (x+3)^2+(y-2)^2=13+12

=> (x+3)^2+(y-2)^2=25=5^2

centre of the circle is ( -3 , 2 )