Question

the centre
s the locus of
of the circle & such
that
2,3 is the mid )
the chord
point of
39-4y+6=0 is​

Answer 1

Answer:

Slope of the given chord =−

2

5

Slop of the line joining the midpoint on the chord and the centre of the circle =(

2+g

3+f

)

(

2

5

)(

2+g

3+f

)=−1

⇒15+5f=4+2g

⇒ Locus is 2x−5y+11=0

solution

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